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Concept:
If sin θ = sin α then θ = nπ + (- 1)n α, α ∈ <-π/2, π/2>, n ∈ Z.
T-Ratios | 0° | 30° | 45° | 60° | 90° |
Sin | 0 | ½ | 1/√2 | √3/2 | 1 |
Cos | 1 | √3/2 | 1/√2 | 1/2 | 0 |
Tan | 0 | 1/√3 | 1 | √3 | Not defined |
Calculation:
Given: 2 sin x – 1 = 0
⇒ sin x = ½ = sin (π/6)
As we know that, if sin θ = sin α then θ = nπ + (- 1)n α, α ∈ <-π/2, π/2>, n ∈ Z.
The general solution of the given equation is: x = nπ + (- 1)n (π/6), where n ∈ Z.Download Solution PDF
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